Ye Olde Inn

Greetings mortals!!

So after realizing I still only have a single set of HQ dice, but an entire tricked out jewelry box full of more types of dice than I knew existed, I was wondering if anyone has ever figured out how the HQ dice match up to standard dice, particularly into an easily findable Chessex set for those looking to play some HQ from all the printed materials but don't have the dice; d4, d6, d8, d10, d12, d20 and a d10 percentile.

On the other side, has anyone created their own die that hold up well over many a session? I've been thinking about stickers but wondering about the peeling off aspect. Custom dice also seem to be massively expensive stateside, anyone come across an Etsy store that does em?

Greetings!

Chcek out this topic as well: viewtopic.php?f=9&t=1057

lorddax wrote:... I was wondering if anyone has ever figured out how the HQ dice match up to standard dice, particularly into an easily findable Chessex set for those looking to play some HQ from all the printed materials but don't have the dice; d4, d6, d8, d10, d12, d20 and a d10 percentile.
...

Well, I am not a mathematician and my English are bad, but it is all about possibilities. I’ve tried to remember some... (I believe I don’t have make mistake...)
At the two first examples I am trying to be more detailed but the third is more difficult.

2d6 for Attack 2= 1d4 where 1 is no skull, 2-3 is one skull, and 4 is two skulls
there are two dices, if the skull is true and the shield is false the possiblilities are the following:
True True
True False
False True
False False

True is 3 skulls per 6 sides= 3/6
False is 3 shiels per 6 sides = 3/6

True True = 3/6 x 3/6 = 9/36
True False = 3/6 x 3/6 = 9/36
False True = 3/6 x 3/6 = 9/36
False False = 3/6 x 3/6 = 9/36

so, two skulls are (True True) = 9/36 = 1/4
one True is (True False) + (False True) = 9/36 + 9/36 = 18/36 = 2/4
none True is (False False) = 9/36 = 1/4

for more complex calculation...
2d6 for Defence 2= 1d10 where 1 is reroll, 2-5 no white shield, 6-9 is one white shield, and 10 is two white shields
there are two dices, if the white shield is true and all the other values are false the possiblilities are the following:
True True
True False
False True
False False

True is 2 white shields per 6 sides= 2/6
False is 4 per 6 sides = 4/6

True True = 2/6 x 2/6 = 4/36
True False = 2/6 x 4/6 = 8/36
False True = 4/6 x 2/6 = 8/36
False False = 4/6 x 4/6 = 16/36

so, two white shields are (True True) = 4/36 = 1/9
one white shield is (True False) + (False True) = 8/36 + 8/36 = 16/36 = 4/9
no white shields is (False False) = 16/36 = 4/9


for a very complexed calculation...
4d6 for Defence 4= 1d100 where 1-19= reroll, 20-35= no shield, 36-67= 1 shield, 68-91 = 2 shields, 92-99 = 3 shield, 100= 4 shields

True is 2 white shields per 6 sides= 2/6
False is 4 per 6 sides = 4/6

four white shields is 2/6 x 2/6 x 2/6 x 2/6 = (2/6)^4 = 16/1296
three white shields is 2/6 x 2/6 x 2/6 x 4/6 = (2/6)^3 x 4/6= 8/216 x 4/6 = 32/1296
two white shields is 2/6 x 2/6 x 4/6 x 4/6 = (2/6)^2 x (4/6)^2 = 4/36 x 16/36 = 64/1296
one white shields is 2/6 x 4/6 x 4/6 x 4/6 = 2/6 x (4/6)^3 = 2/6 x 64/216 = 128/1296
no white shields is 4/6 x 4/6 x 4/6 x 4/6 = (4/6)^4 = 256/1296

four shileds is 16/1296 = 1/81
three shileds (the false can be in four differend ways, T T T F, T T F T, T F T T, F T T T) (32/1296) x 4 = 128/1296 = 8/81
two shileds (the false can be in six differend ways*) (64/1296) x 6 = 384/1296 = 24/81
one shiled (the true can be in four differend ways) (128/1296) x 4 = 512/1296 = 32/81
no shield is 256/1296 = 16/81


*two shields in four dices, can have six differend compilations... F F T T, F T F T, etc...
it is like we have two "F" tring to take one of four possisions
the first "F" will take 1 to 4
the second "F" has one spot less because the first took it... so, it is 1 to 3
it is as we say two "F" where the first has 4 possibilities and the second 3... it is 4/2 x 3/2 = 12/2 = 6

If you want to use just standard six-sided dice as a replacement:
6 = black shield
1/2 = white shield
3/4/5 = skull

that's what I've been using for years.

I just went to the bay and bought a set of dice that were almost mint.

Then to add some flavor I bought some special Hero Quest dice that have some sides with 2 skulls, 2 white shields and 2 black shields.

Thanks for the help

I've been thinking about maybe carving my own dice, then I found out this blog article:

DIY Dice with Laser Printer and Photo Paper

If I can find a decent laser printer I might give this a go. Or does anyone know a good way to do it with an inkjet printer? Inkjets are sadly water soluble.

Found these an okay replacement for now since the gaming table always has an iPhone or iPad present:

HQ Dice for the Mach Dice app

For everyone want it, I’ve calculate and write down the possibilities of the HQ dices... for example, if your hero has 3 Defense, to roll two white shields the possibilities are 6 per 27 or 22%...

Attack with 1 dice : 1xSkull = 3/6, nothing = 3/6
White Shields 1 dice : 1xWhite = 2/6, nothing = 4/6
Black Shields 1 dice : 1xBlack = 1/6, nothing = 5/6
Attack with 2 dices: 2xSkull = 1/4, 1xSkull = 2/4, nothing = 1/4
White Shields 2 dices: 2xWhite = 1/9, 1xWhite = 4/9, nothing = 4/9
Black Shields 2 dices: 2xBlack = 1/39, 1xBlack = 10/39, nothing = 25/39
Attack with 3 dices: 3xSkull = 1/8, 2xSkull = 3/8, 1xSkull = 3/8, nothing = 1/8
White Shields 3 dices: 3xWhite = 1/27, 2xWhite = 6/27, 1xWhite = 12/27, nothing = 8/27
Black Shields 3 dices: 3xBlack = 1/216, 2xBlack = 15/216, 1xBlack = 75/216, nothing = 125/216
Attack with 4 dices: 4xSkull = 1/16, 3xSkull = 20/1296, 2xSkull = 4/16, 1xSkull = 6/16, nothing = 1/16
White Shields 4 dices: 4xWhite = 1/81, 3xWhite = 8/81, 2xWhite = 24/81, 1xWhite = 32/81, nothing = 16/81
Black Shields 4 dices: 4xBlack = 1/1296, 3xBlack = 20/1296, 2xBlack = 150/1296, 1xBlack = 500/1296, nothing = 625/1296
Attack with 5 dices: 5xSkull = 1/32, 4xSkull = 5/32, 3xSkull = 10/32, 2xSkull = 10/32, 1xSkull = 5/32, nothing = 1/32
White Shields 5 dices: 5xWhite = 1/243, 4xWhite = 10/243, 3xWhite = 40/243, 2xWhite = 80/243, 1xWhite = 80/243, nothing = 32/243
Black Shields 5 dices: 5xBlack = 1/7776, 4xBlack = 25/7776, 3xBlack = 250/7776, 2xBlack = 1250/7776, 1xBlack = 3125/7776, nothing = 3125/7776

Wow nice work. Having the probabilities figured out helps in my analysis!

The proper way to do these calculations is with the use of binomial distribution. So for those who want to know how to find a specific probability, I will post the way to do it. Feel free to ask if you don’t understand something.